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Posted by Stinkerbell
- April 10, 2009, 08:21:42 PMQuote from: Mayhem on April 06, 2009, 07:08:37 PMF. One of the above!
A thin piece of wire 40 meters long is cut into two pieces. One piece is used to form a circle with radius r, and the other is used to form a square. No wire is left over. Which of the following represents the total area, in square meters, of the circular and the square regions in terms of r? (p=> Pi)
A. pr2
B. pr2 + 10
C. pr2 + ¼ p2r2
D. pr2 + (40-2pr)2
E. pr2 + (10- ½ pr)2
F. One of the above!
I KNOW that's the right answer!
Posted by disneyland lady
- April 10, 2009, 06:24:49 AMThankfully Sassy has our back when it comes to math. My excuse is that it is Spring Break (somewhere) and I am sure I would get this problem as soon as I go back to/or get some class.
Posted by Hocky
- April 08, 2009, 11:02:49 PMQuote from: Stinkerbell on April 08, 2009, 10:52:10 PM
You just volunteered for the job! Welcome to the club!
Who lil 'ol me?
Thank you........I think......
Posted by Stinkerbell
- April 08, 2009, 10:52:10 PMQuote from: hocky on April 08, 2009, 10:07:28 PM
What if there was a smart a$$ suck up? Who would that be?
You just volunteered for the job! Welcome to the club!
Posted by Hocky
- April 08, 2009, 10:07:28 PMWhat if there was a smart a$$ suck up? Who would that be? 
Posted by Stinkerbell
- April 08, 2009, 05:36:12 PMPosted by Squid
- April 08, 2009, 05:35:13 PM
Posted by ~Sassy~
- April 08, 2009, 05:29:50 PMQuote from: Stinkerbell on April 08, 2009, 03:58:02 PMOne of you ... and one of me is enough.
Smart a$$
Posted by Squid
- April 08, 2009, 05:18:21 PM
Posted by jarjar
- April 08, 2009, 03:59:08 PMQuote from: Stinkerbell on April 08, 2009, 03:58:02 PM
Smart a$$
Posted by Stinkerbell
- April 08, 2009, 03:58:02 PMQuote from: ~Sassy~ on April 08, 2009, 03:42:46 PM
Area of the circle = pi * r^2
Length of left-out wire = 40 - 2*pi*r (The reason behind this is that the circumference will give you the left-out length of the wire.)
If length of the square = a
4a = 40 - 2*pi*r
a = 10 - 1/2*pi*r
So area of the square = a^2 = (10 - 1/2*pi*r) ^ 2
So sum-up = pi * r^2 + (10 - 1/2*pi*r) ^ 2.
The answer is D.
The main reason here is the length of the wire should be equal to the circumference of the objects produced.
It is amazing what you can find on Google.
Smart a$$
Why not just be a suck up like me?Posted by ~Sassy~
- April 08, 2009, 03:42:46 PMQuote from: Mayhem on April 06, 2009, 07:08:37 PM
A thin piece of wire 40 meters long is cut into two pieces. One piece is used to form a circle with radius r, and the other is used to form a square. No wire is left over. Which of the following represents the total area, in square meters, of the circular and the square regions in terms of r? (p=> Pi)
A. pr2
B. pr2 + 10
C. pr2 + ¼ p2r2
D. pr2 + (40-2pr)2
E. pr2 + (10- ½ pr)2
Area of the circle = pi * r^2
Length of left-out wire = 40 - 2*pi*r (The reason behind this is that the circumference will give you the left-out length of the wire.)
If length of the square = a
4a = 40 - 2*pi*r
a = 10 - 1/2*pi*r
So area of the square = a^2 = (10 - 1/2*pi*r) ^ 2
So sum-up = pi * r^2 + (10 - 1/2*pi*r) ^ 2.
The answer is D.
The main reason here is the length of the wire should be equal to the circumference of the objects produced.
It is amazing what you can find on Google.
Posted by Stinkerbell
- April 08, 2009, 03:11:22 PMQuote from: Mayhem on April 08, 2009, 02:17:15 PM
I'm sorry, I meant yes!
It was a typo .. the keys are like right next to eachother
Ah, see. That explains everything... I got your back, Mayhem!
Posted by Mayhem
- April 08, 2009, 02:17:15 PMI'm sorry, I meant yes!
It was a typo .. the keys are like right next to eachother
It was a typo .. the keys are like right next to eachother
Posted by Stinkerbell
- April 08, 2009, 07:04:26 AMQuote from: Mayhem on April 07, 2009, 07:14:13 PM
No
See who comes running to your defense next time someone accuses you of breaking the forum.
